Integrand size = 17, antiderivative size = 61 \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {1}{4 a c^2 \left (1+a^2 x^2\right )}+\frac {x \arctan (a x)}{2 c^2 \left (1+a^2 x^2\right )}+\frac {\arctan (a x)^2}{4 a c^2} \]
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Time = 0.02 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {5012, 267} \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {x \arctan (a x)}{2 c^2 \left (a^2 x^2+1\right )}+\frac {1}{4 a c^2 \left (a^2 x^2+1\right )}+\frac {\arctan (a x)^2}{4 a c^2} \]
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Rule 267
Rule 5012
Rubi steps \begin{align*} \text {integral}& = \frac {x \arctan (a x)}{2 c^2 \left (1+a^2 x^2\right )}+\frac {\arctan (a x)^2}{4 a c^2}-\frac {1}{2} a \int \frac {x}{\left (c+a^2 c x^2\right )^2} \, dx \\ & = \frac {1}{4 a c^2 \left (1+a^2 x^2\right )}+\frac {x \arctan (a x)}{2 c^2 \left (1+a^2 x^2\right )}+\frac {\arctan (a x)^2}{4 a c^2} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.72 \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {1+2 a x \arctan (a x)+\left (1+a^2 x^2\right ) \arctan (a x)^2}{4 c^2 \left (a+a^3 x^2\right )} \]
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Time = 0.30 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.92
method | result | size |
parallelrisch | \(\frac {x^{2} \arctan \left (a x \right )^{2} a^{2}-a^{2} x^{2}+2 x \arctan \left (a x \right ) a +\arctan \left (a x \right )^{2}}{4 c^{2} \left (a^{2} x^{2}+1\right ) a}\) | \(56\) |
derivativedivides | \(\frac {\frac {a x \arctan \left (a x \right )}{2 c^{2} \left (a^{2} x^{2}+1\right )}+\frac {\arctan \left (a x \right )^{2}}{2 c^{2}}-\frac {-\frac {1}{2 \left (a^{2} x^{2}+1\right )}+\frac {\arctan \left (a x \right )^{2}}{2}}{2 c^{2}}}{a}\) | \(66\) |
default | \(\frac {\frac {a x \arctan \left (a x \right )}{2 c^{2} \left (a^{2} x^{2}+1\right )}+\frac {\arctan \left (a x \right )^{2}}{2 c^{2}}-\frac {-\frac {1}{2 \left (a^{2} x^{2}+1\right )}+\frac {\arctan \left (a x \right )^{2}}{2}}{2 c^{2}}}{a}\) | \(66\) |
parts | \(\frac {x \arctan \left (a x \right )}{2 c^{2} \left (a^{2} x^{2}+1\right )}+\frac {\arctan \left (a x \right )^{2}}{2 a \,c^{2}}-\frac {\frac {\arctan \left (a x \right )^{2}}{2 a}-\frac {1}{2 a \left (a^{2} x^{2}+1\right )}}{2 c^{2}}\) | \(70\) |
risch | \(-\frac {\ln \left (i a x +1\right )^{2}}{16 c^{2} a}+\frac {\left (a^{2} x^{2} \ln \left (-i a x +1\right )+\ln \left (-i a x +1\right )-2 i a x \right ) \ln \left (i a x +1\right )}{8 c^{2} \left (a^{2} x^{2}+1\right ) a}-\frac {a^{2} x^{2} \ln \left (-i a x +1\right )^{2}+\ln \left (-i a x +1\right )^{2}-4 i a x \ln \left (-i a x +1\right )-4}{16 c^{2} \left (a x +i\right ) \left (a x -i\right ) a}\) | \(142\) |
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Time = 0.24 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.75 \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {2 \, a x \arctan \left (a x\right ) + {\left (a^{2} x^{2} + 1\right )} \arctan \left (a x\right )^{2} + 1}{4 \, {\left (a^{3} c^{2} x^{2} + a c^{2}\right )}} \]
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Exception generated. \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\text {Exception raised: RecursionError} \]
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Time = 0.29 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.28 \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {1}{2} \, {\left (\frac {x}{a^{2} c^{2} x^{2} + c^{2}} + \frac {\arctan \left (a x\right )}{a c^{2}}\right )} \arctan \left (a x\right ) - \frac {{\left ({\left (a^{2} x^{2} + 1\right )} \arctan \left (a x\right )^{2} - 1\right )} a}{4 \, {\left (a^{4} c^{2} x^{2} + a^{2} c^{2}\right )}} \]
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\[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\int { \frac {\arctan \left (a x\right )}{{\left (a^{2} c x^{2} + c\right )}^{2}} \,d x } \]
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Time = 0.50 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.79 \[ \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^2} \, dx=\frac {a^2\,x^2\,{\mathrm {atan}\left (a\,x\right )}^2+2\,a\,x\,\mathrm {atan}\left (a\,x\right )+{\mathrm {atan}\left (a\,x\right )}^2+1}{4\,a\,c^2\,\left (a^2\,x^2+1\right )} \]
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